-2m^2+10m=-6

Solution for -2m^2+10m=-6 equation:

-2m^2+10m=-6

We move all terms to the left:

-2m^2+10m-(-6)=0

We add all the numbers together, and all the variables

-2m^2+10m+6=0

a = -2; b = 10; c = +6;
Δ = b2-4ac
Δ = 102-4·(-2)·6
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{37}}{2*-2}=\frac{-10-2\sqrt{37}}{-4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{37}}{2*-2}=\frac{-10+2\sqrt{37}}{-4}
$